The procedure for this lab was very similar to the percent acetic acid in vinegar lab. We had to titrate a known substance to calculate the molarity and use the mole ratio to find the molar mass of a different unknown substance when it was titrated. This was another tedious lab because we had to be very precise with our titrations (especially since it's based on percent error). The biggest problem we ran into was the fact that the unknown substance was taking a long time to dissolve. After we gathered our data, the basic approach to solving this lab was to find the Molarity of the NaOH, then use that (with a one to one mole ratio) to find the moles of unknown used. With the moles of unknown, when we divide the mass of the sample by the moles of the sample, we can solve for the molar mass of the unknown substance.
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